(7)/(7x/2)+(7x)/(49x^2-4)=0

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Solution for (7)/(7x/2)+(7x)/(49x^2-4)=0 equation:


D( x )

49*x^2-4 = 0

(7*x)/2 = 0

49*x^2-4 = 0

49*x^2-4 = 0

49*x^2 = 4 // : 49

x^2 = 4/49

x^2 = 4/49 // ^ 1/2

abs(x) = 2/7

x = 2/7 or x = -2/7

(7*x)/2 = 0

(7*x)/2 = 0

7/2*x = 0 // : 7/2

x = 0

x in (-oo:-2/7) U (-2/7:0) U (0:2/7) U (2/7:+oo)

(7*x)/(49*x^2-4)+7/((7*x)/2) = 0

(7*x)/(49*x^2-4)+2/x = 0

(7*x*x)/(x*(49*x^2-4))+(2*(49*x^2-4))/(x*(49*x^2-4)) = 0

2*(49*x^2-4)+7*x*x = 0

105*x^2-8 = 0

(105*x^2-8)/(x*(49*x^2-4)) = 0

(105*x^2-8)/(x*(49*x^2-4)) = 0 // * x*(49*x^2-4)

105*x^2-8 = 0

105*x^2 = 8 // : 105

x^2 = 8/105

x^2 = 8/105 // ^ 1/2

abs(x) = (8/105)^(1/2)

x = (8/105)^(1/2) or x = -(8/105)^(1/2)

x in { (8/105)^(1/2), -(8/105)^(1/2) }

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